# Chain of Responsibilityパターン
#
#Java言語で学ぶデザインパターンと同様の例題をRubyで記述した。
#
# coded by Takehiro Kaga
#

class Trouble
  def initialize(number)
    @number = number
  end
  def number
    @number
  end
end

class Support
  def initialize(name)
    @name = name
    @next = nil
  end
  def name
    @name
  end
  def setNext(nextperson)
    @next = nextperson
  end
  def support(trouble)
    if resolve(trouble) 
      done(trouble)
    elsif @next != nil 
      @next.support(trouble)
    else
      fail(trouble)
    end
  end
  def resolve(trouble)
  end
  def done(trouble)
    puts "[Trouble " + trouble.number.to_s + "]" + " is resolved by " + "[" + self.name + "]."
  end

  def fail(trouble)
    puts "[Trouble " + trouble.number.to_s + "]" + " cannot be resolved."
  end
end

class NoSupport < Support
  def initialize(name)
    super(name)
  end
  def resolve(trouble)
    false
  end
end

class LimitSupport < Support
  def initialize(name, limit)
    super(name)
    @limit = limit
  end
  def resolve(trouble)
    if trouble.number < @limit
      true
    else
      false
    end
  end
end


class OddSupport < Support
  def initialize(name)
    super(name)
  end
  def resolve(trouble)
    if trouble.number % 2 == 1 
      true
    else
      false
    end
  end
end

class SpecialSupport < Support
  def initialize(name, number)
    super(name)
    @number =number
  end
  def resolve(trouble)
    if trouble.number == @number
      true
    else
      false
    end
  end
end


alice = NoSupport.new("Alice")
bob = LimitSupport.new("Bob", 100)
charlie = SpecialSupport.new("Charlie", 429)
diana = LimitSupport.new("Diana", 200)
elmo = OddSupport.new("Elmo")
fred = LimitSupport.new("Fred", 300)

# 連鎖の形成
alice.setNext(bob)
bob.setNext(charlie)
charlie.setNext(diana)
diana.setNext(elmo)
elmo.setNext(fred)

# さまざまなトラブル発生
=begin
i = 0
while i < 500

alice.support(Trouble.new(i))
i += 33

end
=end


0.step(499, 33) { |i| alice.support(Trouble.new(i)) }